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96(x-1)(2x-1)=0
We multiply parentheses ..
96(+2x^2-1x-2x+1)=0
We multiply parentheses
192x^2-96x-192x+96=0
We add all the numbers together, and all the variables
192x^2-288x+96=0
a = 192; b = -288; c = +96;
Δ = b2-4ac
Δ = -2882-4·192·96
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-288)-96}{2*192}=\frac{192}{384} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-288)+96}{2*192}=\frac{384}{384} =1 $
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