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96/2s=3s
We move all terms to the left:
96/2s-(3s)=0
Domain of the equation: 2s!=0We add all the numbers together, and all the variables
s!=0/2
s!=0
s∈R
-3s+96/2s=0
We multiply all the terms by the denominator
-3s*2s+96=0
Wy multiply elements
-6s^2+96=0
a = -6; b = 0; c = +96;
Δ = b2-4ac
Δ = 02-4·(-6)·96
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-6}=\frac{-48}{-12} =+4 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-6}=\frac{48}{-12} =-4 $
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