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960=10x^2
We move all terms to the left:
960-(10x^2)=0
a = -10; b = 0; c = +960;
Δ = b2-4ac
Δ = 02-4·(-10)·960
Δ = 38400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38400}=\sqrt{6400*6}=\sqrt{6400}*\sqrt{6}=80\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{6}}{2*-10}=\frac{0-80\sqrt{6}}{-20} =-\frac{80\sqrt{6}}{-20} =-\frac{4\sqrt{6}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{6}}{2*-10}=\frac{0+80\sqrt{6}}{-20} =\frac{80\sqrt{6}}{-20} =\frac{4\sqrt{6}}{-1} $
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