96=(2x+8)(2x+4)

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Solution for 96=(2x+8)(2x+4) equation:



96=(2x+8)(2x+4)
We move all terms to the left:
96-((2x+8)(2x+4))=0
We multiply parentheses ..
-((+4x^2+8x+16x+32))+96=0
We calculate terms in parentheses: -((+4x^2+8x+16x+32)), so:
(+4x^2+8x+16x+32)
We get rid of parentheses
4x^2+8x+16x+32
We add all the numbers together, and all the variables
4x^2+24x+32
Back to the equation:
-(4x^2+24x+32)
We get rid of parentheses
-4x^2-24x-32+96=0
We add all the numbers together, and all the variables
-4x^2-24x+64=0
a = -4; b = -24; c = +64;
Δ = b2-4ac
Δ = -242-4·(-4)·64
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-40}{2*-4}=\frac{-16}{-8} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+40}{2*-4}=\frac{64}{-8} =-8 $

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