96=(3x+5)x

Solution for 96=(3x+5)x equation:

96=(3x+5)x

We move all terms to the left:

96-((3x+5)x)=0


We calculate terms in parentheses: -((3x+5)x), so:

(3x+5)x

We multiply parentheses

3x^2+5x

Back to the equation:

-(3x^2+5x)


We get rid of parentheses

-3x^2-5x+96=0

a = -3; b = -5; c = +96;
Δ = b2-4ac
Δ = -52-4·(-3)·96
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1177}}{2*-3}=\frac{5-\sqrt{1177}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1177}}{2*-3}=\frac{5+\sqrt{1177}}{-6}
$