96=(4+2x)(x)

Solution for 96=(4+2x)(x) equation:

96=(4+2x)(x)

We move all terms to the left:

96-((4+2x)(x))=0

We add all the numbers together, and all the variables

-((2x+4)x)+96=0


We calculate terms in parentheses: -((2x+4)x), so:

(2x+4)x

We multiply parentheses

2x^2+4x

Back to the equation:

-(2x^2+4x)


We get rid of parentheses

-2x^2-4x+96=0

a = -2; b = -4; c = +96;
Δ = b2-4ac
Δ = -42-4·(-2)·96
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-28}{2*-2}=\frac{-24}{-4}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+28}{2*-2}=\frac{32}{-4}
=-8
$