96=(x+5)(x+1)

Solution for 96=(x+5)(x+1) equation:

96=(x+5)(x+1)

We move all terms to the left:

96-((x+5)(x+1))=0

We multiply parentheses ..

-((+x^2+x+5x+5))+96=0


We calculate terms in parentheses: -((+x^2+x+5x+5)), so:

(+x^2+x+5x+5)

We get rid of parentheses

x^2+x+5x+5

We add all the numbers together, and all the variables

x^2+6x+5

Back to the equation:

-(x^2+6x+5)


We get rid of parentheses

-x^2-6x-5+96=0

We add all the numbers together, and all the variables

-1x^2-6x+91=0

a = -1; b = -6; c = +91;
Δ = b2-4ac
Δ = -62-4·(-1)·91
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-20}{2*-1}=\frac{-14}{-2}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+20}{2*-1}=\frac{26}{-2}
=-13
$