96=(x+5)(x+9)

Solution for 96=(x+5)(x+9) equation:

96=(x+5)(x+9)

We move all terms to the left:

96-((x+5)(x+9))=0

We multiply parentheses ..

-((+x^2+9x+5x+45))+96=0


We calculate terms in parentheses: -((+x^2+9x+5x+45)), so:

(+x^2+9x+5x+45)

We get rid of parentheses

x^2+9x+5x+45

We add all the numbers together, and all the variables

x^2+14x+45

Back to the equation:

-(x^2+14x+45)


We get rid of parentheses

-x^2-14x-45+96=0

We add all the numbers together, and all the variables

-1x^2-14x+51=0

a = -1; b = -14; c = +51;
Δ = b2-4ac
Δ = -142-4·(-1)·51
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-20}{2*-1}=\frac{-6}{-2}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+20}{2*-1}=\frac{34}{-2}
=-17
$