96=0.5(x+4)x

Solution for 96=0.5(x+4)x equation:

96=0.5(x+4)x

We move all terms to the left:

96-(0.5(x+4)x)=0


We calculate terms in parentheses: -(0.5(x+4)x), so:

0.5(x+4)x

We multiply parentheses

0x^2+0x

We add all the numbers together, and all the variables

x^2+x

Back to the equation:

-(x^2+x)


We get rid of parentheses

-x^2-x+96=0

We add all the numbers together, and all the variables

-1x^2-1x+96=0

a = -1; b = -1; c = +96;
Δ = b2-4ac
Δ = -12-4·(-1)·96
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{385}}{2*-1}=\frac{1-\sqrt{385}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{385}}{2*-1}=\frac{1+\sqrt{385}}{-2}
$