96q+92*(1-q)=100q+90*(1-q)

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Solution for 96q+92*(1-q)=100q+90*(1-q) equation:



96q+92(1-q)=100q+90(1-q)
We move all terms to the left:
96q+92(1-q)-(100q+90(1-q))=0
We add all the numbers together, and all the variables
96q+92(-1q+1)-(100q+90(-1q+1))=0
We multiply parentheses
96q-92q-(100q+90(-1q+1))+92=0
We calculate terms in parentheses: -(100q+90(-1q+1)), so:
100q+90(-1q+1)
We multiply parentheses
100q-90q+90
We add all the numbers together, and all the variables
10q+90
Back to the equation:
-(10q+90)
We add all the numbers together, and all the variables
4q-(10q+90)+92=0
We get rid of parentheses
4q-10q-90+92=0
We add all the numbers together, and all the variables
-6q+2=0
We move all terms containing q to the left, all other terms to the right
-6q=-2
q=-2/-6
q=1/3

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