96q+92*(1-q)=100q+90*(1-q)

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Solution for 96q+92*(1-q)=100q+90*(1-q) equation: 



96q+92(1-q)=100q+90(1-q)

We move all terms to the left:

96q+92(1-q)-(100q+90(1-q))=0

We add all the numbers together, and all the variables

96q+92(-1q+1)-(100q+90(-1q+1))=0

We multiply parentheses

96q-92q-(100q+90(-1q+1))+92=0



We calculate terms in parentheses: -(100q+90(-1q+1)), so:

100q+90(-1q+1)

We multiply parentheses

100q-90q+90

We add all the numbers together, and all the variables

10q+90

Back to the equation:

-(10q+90)



We add all the numbers together, and all the variables

4q-(10q+90)+92=0

We get rid of parentheses

4q-10q-90+92=0

We add all the numbers together, and all the variables

-6q+2=0

We move all terms containing q to the left, all other terms to the right

-6q=-2

q=-2/-6

q=1/3

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