97-108=-4(-6y)-13(2y)+4

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Solution for 97-108=-4(-6y)-13(2y)+4 equation: 



97-108=-4(-6y)-13(2y)+4

We move all terms to the left:

97-108-(-4(-6y)-13(2y)+4)=0

We add all the numbers together, and all the variables

-(-4(-6y)-132y+4)-11=0



We calculate terms in parentheses: -(-4(-6y)-132y+4), so:

-4(-6y)-132y+4

We add all the numbers together, and all the variables

-132y-4(-6y)+4

We multiply parentheses

-132y+24y+4

We add all the numbers together, and all the variables

-108y+4

Back to the equation:

-(-108y+4)



We get rid of parentheses

108y-4-11=0

We add all the numbers together, and all the variables

108y-15=0

We move all terms containing y to the left, all other terms to the right

108y=15

y=15/108

y=5/36

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