98-7/3x+5=3x-4/x+6

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Solution for 98-7/3x+5=3x-4/x+6 equation: 



98-7/3x+5=3x-4/x+6

We move all terms to the left:

98-7/3x+5-(3x-4/x+6)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: x+6)!=0

x∈R



We add all the numbers together, and all the variables

-7/3x-(3x-4/x+6)+103=0

We get rid of parentheses

-7/3x-3x+4/x-6+103=0

We calculate fractions


-3x+(-7x)/3x^2+12x/3x^2-6+103=0

We add all the numbers together, and all the variables

-3x+(-7x)/3x^2+12x/3x^2+97=0

We multiply all the terms by the denominator


-3x*3x^2+(-7x)+12x+97*3x^2=0

We add all the numbers together, and all the variables

12x-3x*3x^2+(-7x)+97*3x^2=0

Wy multiply elements

-9x^3+291x^2+12x+(-7x)=0

We get rid of parentheses

-9x^3+291x^2+12x-7x=0

We do not support expression: x^3

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