98-75/(39-12z)=73

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Solution for 98-75/(39-12z)=73 equation: 



98-75/(39-12z)=73

We move all terms to the left:

98-75/(39-12z)-(73)=0



Domain of the equation: (39-12z)!=0

We move all terms containing z to the left, all other terms to the right

-12z!=-39

z!=-39/-12

z!=3+1/4

z∈R



We add all the numbers together, and all the variables

-75/(-12z+39)+98-73=0

We add all the numbers together, and all the variables

-75/(-12z+39)+25=0

We multiply all the terms by the denominator


25*(-12z+39)-75=0

We multiply parentheses

-300z+975-75=0

We add all the numbers together, and all the variables

-300z+900=0

We move all terms containing z to the left, all other terms to the right

-300z=-900

z=-900/-300

z=+3

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