98=(2*98/h)*h

Solution for 98=(2*98/h)*h equation:

98=(2*98/h)*h

We move all terms to the left:

98-((2*98/h)*h)=0


Domain of the equation: h)*h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

-((+2*98/h)*h)+98=0

We multiply all the terms by the denominator


-((+2*98+98*h)*h)=0


We calculate terms in parentheses: -((+2*98+98*h)*h), so:

(+2*98+98*h)*h

We add all the numbers together, and all the variables

(98h+196)*h

We multiply parentheses

98h^2+196h

Back to the equation:

-(98h^2+196h)


We get rid of parentheses

-98h^2-196h=0

a = -98; b = -196; c = 0;
Δ = b2-4ac
Δ = -1962-4·(-98)·0
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-196}{2*-98}=\frac{0}{-196}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+196}{2*-98}=\frac{392}{-196}
=-2
$