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98=1+(3/20)x
We move all terms to the left:
98-(1+(3/20)x)=0
Domain of the equation: 20)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(1+(+3/20)x)+98=0
We multiply all the terms by the denominator
-(1+(+3+98*20)x)=0
We calculate terms in parentheses: -(1+(+3+98*20)x), so:We get rid of parentheses
1+(+3+98*20)x
determiningTheFunctionDomain (+3+98*20)x+1
We add all the numbers together, and all the variables
1963x+1
Back to the equation:
-(1963x+1)
-1963x-1=0
We move all terms containing x to the left, all other terms to the right
-1963x=1
x=1/-1963
x=-1/1963
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