98=2x*3x

Solution for 98=2x*3x equation:

98=2x*3x

We move all terms to the left:

98-(2x*3x)=0

We add all the numbers together, and all the variables

-(+2x*3x)+98=0

We get rid of parentheses

-2x*3x+98=0

Wy multiply elements

-6x^2+98=0

a = -6; b = 0; c = +98;
Δ = b2-4ac
Δ = 02-4·(-6)·98
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{3}}{2*-6}=\frac{0-28\sqrt{3}}{-12}
=-\frac{28\sqrt{3}}{-12}
=-\frac{7\sqrt{3}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{3}}{2*-6}=\frac{0+28\sqrt{3}}{-12}
=\frac{28\sqrt{3}}{-12}
=\frac{7\sqrt{3}}{-3}
$