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98x^2=206
We move all terms to the left:
98x^2-(206)=0
a = 98; b = 0; c = -206;
Δ = b2-4ac
Δ = 02-4·98·(-206)
Δ = 80752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80752}=\sqrt{784*103}=\sqrt{784}*\sqrt{103}=28\sqrt{103}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{103}}{2*98}=\frac{0-28\sqrt{103}}{196} =-\frac{28\sqrt{103}}{196} =-\frac{\sqrt{103}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{103}}{2*98}=\frac{0+28\sqrt{103}}{196} =\frac{28\sqrt{103}}{196} =\frac{\sqrt{103}}{7} $
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