99=1/2(10)(4+b2)

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Solution for 99=1/2(10)(4+b2) equation: 



99=1/2(10)(4+b2)

We move all terms to the left:

99-(1/2(10)(4+b2))=0



Domain of the equation: 210(4+b2))!=0

b∈R



We add all the numbers together, and all the variables

-(1/210(+b^2+4))+99=0

We multiply all the terms by the denominator


-(1+99*210(+b^2+4))=0



We calculate terms in parentheses: -(1+99*210(+b^2+4)), so:

1+99*210(+b^2+4)

determiningTheFunctionDomain
99*210(+b^2+4)+1

Wy multiply elements

20790b(++1

We use the square of the difference formula

20790b(+1

Back to the equation:

-(20790b(+1)



We add all the numbers together, and all the variables

-(20790b1=0

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