99=3(4b-5)

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Solution for 99=3(4b-5) equation:



99=3(4b-5)
We move all terms to the left:
99-(3(4b-5))=0
We calculate terms in parentheses: -(3(4b-5)), so:
3(4b-5)
We multiply parentheses
12b-15
Back to the equation:
-(12b-15)
We get rid of parentheses
-12b+15+99=0
We add all the numbers together, and all the variables
-12b+114=0
We move all terms containing b to the left, all other terms to the right
-12b=-114
b=-114/-12
b=9+1/2

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