99=33x+3(3x+15)

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Solution for 99=33x+3(3x+15) equation:



99=33x+3(3x+15)
We move all terms to the left:
99-(33x+3(3x+15))=0
We calculate terms in parentheses: -(33x+3(3x+15)), so:
33x+3(3x+15)
We multiply parentheses
33x+9x+45
We add all the numbers together, and all the variables
42x+45
Back to the equation:
-(42x+45)
We get rid of parentheses
-42x-45+99=0
We add all the numbers together, and all the variables
-42x+54=0
We move all terms containing x to the left, all other terms to the right
-42x=-54
x=-54/-42
x=1+2/7

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