99=33x+3(3x+15)

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Solution for 99=33x+3(3x+15) equation: 



99=33x+3(3x+15)

We move all terms to the left:

99-(33x+3(3x+15))=0



We calculate terms in parentheses: -(33x+3(3x+15)), so:

33x+3(3x+15)

We multiply parentheses

33x+9x+45

We add all the numbers together, and all the variables

42x+45

Back to the equation:

-(42x+45)



We get rid of parentheses

-42x-45+99=0

We add all the numbers together, and all the variables

-42x+54=0

We move all terms containing x to the left, all other terms to the right

-42x=-54

x=-54/-42

x=1+2/7

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