99x2+149x+56=0

Solution for 99x2+149x+56=0 equation:

99x^2+149x+56=0

a = 99; b = 149; c = +56;
Δ = b2-4ac
Δ = 1492-4·99·56
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(149)-5}{2*99}=\frac{-154}{198}
=-7/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(149)+5}{2*99}=\frac{-144}{198}
=-8/11
$