99x2-73x+10=0

Solution for 99x2-73x+10=0 equation:

99x^2-73x+10=0

a = 99; b = -73; c = +10;
Δ = b2-4ac
Δ = -732-4·99·10
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-37}{2*99}=\frac{36}{198}
=2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+37}{2*99}=\frac{110}{198}
=5/9
$