9=(28/11)+b

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Solution for 9=(28/11)+b equation: 



9=(28/11)+b

We move all terms to the left:

9-((28/11)+b)=0



Domain of the equation: 11)+b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-((+28/11)+b)+9=0

We multiply all the terms by the denominator


-((+28+9*11)+b)=0



We calculate terms in parentheses: -((+28+9*11)+b), so:

(+28+9*11)+b

determiningTheFunctionDomain
b+(+28+9*11)

We add all the numbers together, and all the variables

b+127

Back to the equation:

-(b+127)



We get rid of parentheses

-b-127=0

We add all the numbers together, and all the variables

-1b-127=0

We move all terms containing b to the left, all other terms to the right

-b=127

b=127/-1

b=-127

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