9=(8d-5)+13=12d-2

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Solution for 9=(8d-5)+13=12d-2 equation:



9=(8d-5)+13=12d-2
We move all terms to the left:
9-((8d-5)+13)=0
We calculate terms in parentheses: -((8d-5)+13), so:
(8d-5)+13
We get rid of parentheses
8d-5+13
We add all the numbers together, and all the variables
8d+8
Back to the equation:
-(8d+8)
We get rid of parentheses
-8d-8+9=0
We add all the numbers together, and all the variables
-8d+1=0
We move all terms containing d to the left, all other terms to the right
-8d=-1
d=-1/-8
d=1/8

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