9=(8d-5)+13=12d-2

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Solution for 9=(8d-5)+13=12d-2 equation: 



9=(8d-5)+13=12d-2

We move all terms to the left:

9-((8d-5)+13)=0



We calculate terms in parentheses: -((8d-5)+13), so:

(8d-5)+13

We get rid of parentheses

8d-5+13

We add all the numbers together, and all the variables

8d+8

Back to the equation:

-(8d+8)



We get rid of parentheses

-8d-8+9=0

We add all the numbers together, and all the variables

-8d+1=0

We move all terms containing d to the left, all other terms to the right

-8d=-1

d=-1/-8

d=1/8

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