9=(x-5)-(x-2)+6x

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Solution for 9=(x-5)-(x-2)+6x equation: 



9=(x-5)-(x-2)+6x

We move all terms to the left:

9-((x-5)-(x-2)+6x)=0



We calculate terms in parentheses: -((x-5)-(x-2)+6x), so:

(x-5)-(x-2)+6x

We add all the numbers together, and all the variables

6x+(x-5)-(x-2)

We get rid of parentheses

6x+x-x-5+2

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

-6x+3+9=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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