9=-28n/5-3(4n/5-2)

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Solution for 9=-28n/5-3(4n/5-2) equation: 


n in (-oo:+oo)

9 = (-28*n)/5-(3*((4*n)/5-2)) // - (-28*n)/5-(3*((4*n)/5-2))

3*((4*n)/5-2)-((-28*n)/5)+9 = 0

3*((4*n)/5-2)+(28/5)*n+9 = 0

3*(4/5*n-2)+(28*n)/5+9 = 0

(3*5*(4/5*n-2))/5+(28*n)/5+(5*9)/5 = 0

3*5*(4/5*n-2)+28*n+5*9 = 0

40*n-30+45 = 0

40*n+15 = 0

(40*n+15)/5 = 0

(40*n+15)/5 = 0 // * 5

40*n+15 = 0

40*n+15 = 0 // - 15

40*n = -15 // : 40

n = -15/40

n = -3/8

n = -3/8

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