9=1/2(6)(b1+b2)

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Solution for 9=1/2(6)(b1+b2) equation:



9=1/2(6)(b1+b2)
We move all terms to the left:
9-(1/2(6)(b1+b2))=0
Domain of the equation: 26(b1+b2))!=0
b∈R
We add all the numbers together, and all the variables
-(1/26(+b+b^2))+9=0
We multiply all the terms by the denominator
-(1+9*26(+b+b^2))=0
We calculate terms in parentheses: -(1+9*26(+b+b^2)), so:
1+9*26(+b+b^2)
determiningTheFunctionDomain 9*26(+b+b^2)+1
Wy multiply elements
234b(++1
We use the square of the difference formula
234b(+1
Back to the equation:
-(234b(+1)
We add all the numbers together, and all the variables
-(234b1=0

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