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9=1/2(x+4)
We move all terms to the left:
9-(1/2(x+4))=0
Domain of the equation: 2(x+4))!=0We multiply all the terms by the denominator
x∈R
-(1+9*2(x+4))=0
We calculate terms in parentheses: -(1+9*2(x+4)), so:
1+9*2(x+4)
determiningTheFunctionDomain 9*2(x+4)+1
Wy multiply elements
18x(x+1
Back to the equation:
-(18x(x+1)
We calculate terms in parentheses: -(18x(x+1), so:
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We calculate terms in parentheses: -(18x(x+1), so:
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We calculate terms in parentheses: -(18x(x+1), so:
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We calculate terms in parentheses: -(18x(x+1), so:
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We calculate terms in parentheses: -(18x(x+1), so:
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We calculate terms in parentheses: -(18x(x+1), so:
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We calculate terms in parentheses: -(18x(x+1), so:
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