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9=1/2v+3
We move all terms to the left:
9-(1/2v+3)=0
Domain of the equation: 2v+3)!=0We get rid of parentheses
v∈R
-1/2v-3+9=0
We multiply all the terms by the denominator
-3*2v+9*2v-1=0
Wy multiply elements
-6v+18v-1=0
We add all the numbers together, and all the variables
12v-1=0
We move all terms containing v to the left, all other terms to the right
12v=1
v=1/12
v=1/12
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