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9=10(x-2)3x
We move all terms to the left:
9-(10(x-2)3x)=0
We calculate terms in parentheses: -(10(x-2)3x), so:We get rid of parentheses
10(x-2)3x
We multiply parentheses
30x^2-60x
Back to the equation:
-(30x^2-60x)
-30x^2+60x+9=0
a = -30; b = 60; c = +9;
Δ = b2-4ac
Δ = 602-4·(-30)·9
Δ = 4680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4680}=\sqrt{36*130}=\sqrt{36}*\sqrt{130}=6\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-6\sqrt{130}}{2*-30}=\frac{-60-6\sqrt{130}}{-60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+6\sqrt{130}}{2*-30}=\frac{-60+6\sqrt{130}}{-60} $
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