9=3(b-2)

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Solution for 9=3(b-2) equation:



9=3(b-2)
We move all terms to the left:
9-(3(b-2))=0
We calculate terms in parentheses: -(3(b-2)), so:
3(b-2)
We multiply parentheses
3b-6
Back to the equation:
-(3b-6)
We get rid of parentheses
-3b+6+9=0
We add all the numbers together, and all the variables
-3b+15=0
We move all terms containing b to the left, all other terms to the right
-3b=-15
b=-15/-3
b=+5

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