If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9=3(j-7)
We move all terms to the left:
9-(3(j-7))=0
We calculate terms in parentheses: -(3(j-7)), so:We get rid of parentheses
3(j-7)
We multiply parentheses
3j-21
Back to the equation:
-(3j-21)
-3j+21+9=0
We add all the numbers together, and all the variables
-3j+30=0
We move all terms containing j to the left, all other terms to the right
-3j=-30
j=-30/-3
j=+10
| 3x=5(x-4)-10 | | 277.4=n÷3.5 | | -t+1=13 | | 18d-17d=5 | | -2/3x+15=75 | | 4x2-12x-7=0 | | 7y-21+14=21 | | 7+35n+6+24=13 | | 6(15/6x+3/2)=97 | | 19d-9d=10 | | 17+8(x–3)=8x–9 | | x-10/396=-22 | | 277A=n/3.5 | | 16x=35=9x | | x–3=–17 | | 12/50=3/x | | 3x^-7x=x | | -7(3-6m)=20+m | | n/8=64 | | 8p-3=(5p+9) | | x+12/2=10 | | 0.9p+3.2=-1.7p | | 6k+(3•10-8)=(2•3)k+22 | | 9a-45=56 | | 4(x-6)=4x+6 | | 5x+4-7x=4x+16 | | 2x-11+90=180 | | −2+3x=−(x+6) | | 26-2v=2v-(v-2) | | 10x/20=4 | | 4x+3x=120 | | 10(x-2)=40 |