9=3/4(n+3)

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Solution for 9=3/4(n+3) equation: 



9=3/4(n+3)

We move all terms to the left:

9-(3/4(n+3))=0



Domain of the equation: 4(n+3))!=0

n∈R



We multiply all the terms by the denominator


-(3+9*4(n+3))=0



We calculate terms in parentheses: -(3+9*4(n+3)), so:

3+9*4(n+3)

determiningTheFunctionDomain
9*4(n+3)+3

Wy multiply elements

36n(n+3

Back to the equation:

-(36n(n+3)





We calculate terms in parentheses: -(36n(n+3), so:

36n(n+3





We calculate terms in parentheses: -(36n(n+3), so:

36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





We calculate terms in parentheses: -(36n(n+3), so:

36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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36n(n+3





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