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9=4+(1/5q)
We move all terms to the left:
9-(4+(1/5q))=0
Domain of the equation: 5q))!=0We add all the numbers together, and all the variables
q!=0/1
q!=0
q∈R
-(4+(+1/5q))+9=0
We multiply all the terms by the denominator
-(4+(+1+9*5q))=0
We calculate terms in parentheses: -(4+(+1+9*5q)), so:We get rid of parentheses
4+(+1+9*5q)
determiningTheFunctionDomain (+1+9*5q)+4
We add all the numbers together, and all the variables
(9*5q+1)+4
We get rid of parentheses
9*5q+1+4
We add all the numbers together, and all the variables
9*5q+5
Wy multiply elements
45q+5
Back to the equation:
-(45q+5)
-45q-5=0
We move all terms containing q to the left, all other terms to the right
-45q=5
q=5/-45
q=-1/9
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