9=48+-4.9x2

Solution for 9=48+-4.9x2 equation:

9=48+-4.9x^2

We move all terms to the left:

9-(48+-4.9x^2)=0

We use the square of the difference formula

-(48-4.9x^2)+9=0

We get rid of parentheses

4.9x^2-48+9=0

We add all the numbers together, and all the variables

4.9x^2-39=0

a = 4.9; b = 0; c = -39;
Δ = b2-4ac
Δ = 02-4·4.9·(-39)
Δ = 764.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{764.4}}{2*4.9}=\frac{0-\sqrt{764.4}}{9.8}
=-\frac{\sqrt{}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{764.4}}{2*4.9}=\frac{0+\sqrt{764.4}}{9.8}
=\frac{\sqrt{}}{9.8}
$