9=6-(k+2)

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Solution for 9=6-(k+2) equation: 



9=6-(k+2)

We move all terms to the left:

9-(6-(k+2))=0



We calculate terms in parentheses: -(6-(k+2)), so:

6-(k+2)

determiningTheFunctionDomain
-(k+2)+6

We get rid of parentheses

-k-2+6

We add all the numbers together, and all the variables

-1k+4

Back to the equation:

-(-1k+4)



We get rid of parentheses

1k-4+9=0

We add all the numbers together, and all the variables

k+5=0

We move all terms containing k to the left, all other terms to the right

k=-5

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