9=8c+15c/c

Solution for 9=8c+15c/c equation:

9=8c+15c/c

We move all terms to the left:

9-(8c+15c/c)=0


Domain of the equation: c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

-(+8c+15c/c)+9=0

We get rid of parentheses

-8c-15c/c+9=0

We multiply all the terms by the denominator


-8c*c-15c+9*c=0

We add all the numbers together, and all the variables

-6c-8c*c=0

Wy multiply elements

-8c^2-6c=0

a = -8; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-8)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-8}=\frac{0}{-16}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-8}=\frac{12}{-16}
=-3/4
$