9=b(b-8)

Solution for 9=b(b-8) equation:

Simplifying
9 = b(b + -8)

Reorder the terms:
9 = b(-8 + b)
9 = (-8 * b + b * b)
9 = (-8b + b2)

Solving
9 = -8b + b2

Solving for variable 'b'.

Reorder the terms:
9 + 8b + -1b2 = -8b + 8b + b2 + -1b2

Combine like terms: -8b + 8b = 0
9 + 8b + -1b2 = 0 + b2 + -1b2
9 + 8b + -1b2 = b2 + -1b2

Combine like terms: b2 + -1b2 = 0
9 + 8b + -1b2 = 0

Factor a trinomial.
(9 + -1b)(1 + b) = 0

Subproblem 1
Set the factor '(9 + -1b)' equal to zero and attempt to solve:

Simplifying
9 + -1b = 0

Solving
9 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1b = 0 + -9
-1b = 0 + -9

Combine like terms: 0 + -9 = -9
-1b = -9

Divide each side by '-1'.
b = 9

Simplifying
b = 9
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {9, -1}