9=n(n+3)/2

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Solution for 9=n(n+3)/2 equation:



9=n(n+3)/2
We move all terms to the left:
9-(n(n+3)/2)=0
We multiply all the terms by the denominator
-(n(n+3)+9*2)=0
We calculate terms in parentheses: -(n(n+3)+9*2), so:
n(n+3)+9*2
We add all the numbers together, and all the variables
n(n+3)+18
We multiply parentheses
n^2+3n+18
Back to the equation:
-(n^2+3n+18)
We get rid of parentheses
-n^2-3n-18=0
We add all the numbers together, and all the variables
-1n^2-3n-18=0
a = -1; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·(-1)·(-18)
Δ = -63
Delta is less than zero, so there is no solution for the equation

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