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9=y+1/5y
We move all terms to the left:
9-(y+1/5y)=0
Domain of the equation: 5y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-(+y+1/5y)+9=0
We get rid of parentheses
-y-1/5y+9=0
We multiply all the terms by the denominator
-y*5y+9*5y-1=0
Wy multiply elements
-5y^2+45y-1=0
a = -5; b = 45; c = -1;
Δ = b2-4ac
Δ = 452-4·(-5)·(-1)
Δ = 2005
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2005}}{2*-5}=\frac{-45-\sqrt{2005}}{-10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2005}}{2*-5}=\frac{-45+\sqrt{2005}}{-10} $
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