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9=y2+2y+2y+4
We move all terms to the left:
9-(y2+2y+2y+4)=0
We add all the numbers together, and all the variables
-(+y^2+4y+4)+9=0
We get rid of parentheses
-y^2-4y-4+9=0
We add all the numbers together, and all the variables
-1y^2-4y+5=0
a = -1; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·(-1)·5
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6}{2*-1}=\frac{-2}{-2} =1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6}{2*-1}=\frac{10}{-2} =-5 $
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