9K-3(k-6)=4(k+10)-8

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Solution for 9K-3(k-6)=4(k+10)-8 equation: 



9-3(K-6)=4(K+10)-8

We move all terms to the left:

9-3(K-6)-(4(K+10)-8)=0

We multiply parentheses

-3K-(4(K+10)-8)+18+9=0



We calculate terms in parentheses: -(4(K+10)-8), so:

4(K+10)-8

We multiply parentheses

4K+40-8

We add all the numbers together, and all the variables

4K+32

Back to the equation:

-(4K+32)



We add all the numbers together, and all the variables

-3K-(4K+32)+27=0

We get rid of parentheses

-3K-4K-32+27=0

We add all the numbers together, and all the variables

-7K-5=0

We move all terms containing K to the left, all other terms to the right

-7K=5

K=5/-7

K=-5/7

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