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9X^2+36X-35=0
a = 9; b = 36; c = -35;
Δ = b2-4ac
Δ = 362-4·9·(-35)
Δ = 2556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2556}=\sqrt{36*71}=\sqrt{36}*\sqrt{71}=6\sqrt{71}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6\sqrt{71}}{2*9}=\frac{-36-6\sqrt{71}}{18} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6\sqrt{71}}{2*9}=\frac{-36+6\sqrt{71}}{18} $
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