9a-4=3(a-11)-23

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Solution for 9a-4=3(a-11)-23 equation: 



9a-4=3(a-11)-23

We move all terms to the left:

9a-4-(3(a-11)-23)=0



We calculate terms in parentheses: -(3(a-11)-23), so:

3(a-11)-23

We multiply parentheses

3a-33-23

We add all the numbers together, and all the variables

3a-56

Back to the equation:

-(3a-56)



We get rid of parentheses

9a-3a+56-4=0

We add all the numbers together, and all the variables

6a+52=0

We move all terms containing a to the left, all other terms to the right

6a=-52

a=-52/6

a=-8+2/3

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