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9a^2-30a+16=0
a = 9; b = -30; c = +16;
Δ = b2-4ac
Δ = -302-4·9·16
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-18}{2*9}=\frac{12}{18} =2/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+18}{2*9}=\frac{48}{18} =2+2/3 $
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