9b+36=3(-5b+2)-6b

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Solution for 9b+36=3(-5b+2)-6b equation: 



9b+36=3(-5b+2)-6b

We move all terms to the left:

9b+36-(3(-5b+2)-6b)=0



We calculate terms in parentheses: -(3(-5b+2)-6b), so:

3(-5b+2)-6b

We add all the numbers together, and all the variables

-6b+3(-5b+2)

We multiply parentheses

-6b-15b+6

We add all the numbers together, and all the variables

-21b+6

Back to the equation:

-(-21b+6)



We get rid of parentheses

9b+21b-6+36=0

We add all the numbers together, and all the variables

30b+30=0

We move all terms containing b to the left, all other terms to the right

30b=-30

b=-30/30

b=-1

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