9b+5=3(3b-2)+11

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Solution for 9b+5=3(3b-2)+11 equation: 



9b+5=3(3b-2)+11

We move all terms to the left:

9b+5-(3(3b-2)+11)=0



We calculate terms in parentheses: -(3(3b-2)+11), so:

3(3b-2)+11

We multiply parentheses

9b-6+11

We add all the numbers together, and all the variables

9b+5

Back to the equation:

-(9b+5)



We get rid of parentheses

9b-9b-5+5=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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