9b-21=3(b-7)+6b

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Solution for 9b-21=3(b-7)+6b equation: 



9b-21=3(b-7)+6b

We move all terms to the left:

9b-21-(3(b-7)+6b)=0



We calculate terms in parentheses: -(3(b-7)+6b), so:

3(b-7)+6b

We add all the numbers together, and all the variables

6b+3(b-7)

We multiply parentheses

6b+3b-21

We add all the numbers together, and all the variables

9b-21

Back to the equation:

-(9b-21)



We get rid of parentheses

9b-9b+21-21=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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