9b-3(b+6)=2(b+1)

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Solution for 9b-3(b+6)=2(b+1) equation:


Simplifying
9b + -3(b + 6) = 2(b + 1)

Reorder the terms:
9b + -3(6 + b) = 2(b + 1)
9b + (6 * -3 + b * -3) = 2(b + 1)
9b + (-18 + -3b) = 2(b + 1)

Reorder the terms:
-18 + 9b + -3b = 2(b + 1)

Combine like terms: 9b + -3b = 6b
-18 + 6b = 2(b + 1)

Reorder the terms:
-18 + 6b = 2(1 + b)
-18 + 6b = (1 * 2 + b * 2)
-18 + 6b = (2 + 2b)

Solving
-18 + 6b = 2 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-18 + 6b + -2b = 2 + 2b + -2b

Combine like terms: 6b + -2b = 4b
-18 + 4b = 2 + 2b + -2b

Combine like terms: 2b + -2b = 0
-18 + 4b = 2 + 0
-18 + 4b = 2

Add '18' to each side of the equation.
-18 + 18 + 4b = 2 + 18

Combine like terms: -18 + 18 = 0
0 + 4b = 2 + 18
4b = 2 + 18

Combine like terms: 2 + 18 = 20
4b = 20

Divide each side by '4'.
b = 5

Simplifying
b = 5

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