9b-45=3(b-15)

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Solution for 9b-45=3(b-15) equation: 



9b-45=3(b-15)

We move all terms to the left:

9b-45-(3(b-15))=0



We calculate terms in parentheses: -(3(b-15)), so:

3(b-15)

We multiply parentheses

3b-45

Back to the equation:

-(3b-45)



We get rid of parentheses

9b-3b+45-45=0

We add all the numbers together, and all the variables

6b=0

b=0/6

b=0

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